Right around NFL Draft season is when rumors and speculation run rampant on what each and every team will do both leading up to, and during the draft. While most of the focus is far and away not the actual picks, with potential trades being second, there is also speculation on just who may get released. For the Tampa Bay Buccaneers, they are no different, despite being in a much better position than the rest of the league. What with having all 22 starters on a Super Bowl-winning team and all. You know, that old chestnut.
With a crowded, and talented, tight end room, there is reason to believe that one such move may come from here. It’s safe to assume that Rob Gronkowski is pretty much untouchable, which basically leaves O.J. Howard and Cameron Brate. As much as it may sting, especially considering that Howard is a former first-round pick, he should be the one to go.
Now of course, in a perfect (and very possible) world, the Buccaneers may not have to let any of their tight ends go. The point is, that even though cutting bait with Brate would save the Buccaneers an additional seven million dollars in cap space, they need to do whatever they can to make sure he sticks around. Here are three reasons why.