Buccaneers now only team in division with proven quarterback
Thanks to the trade of Matt Ryan, the Tampa Bay Buccaneers are now the only team in the division with a proven, or even actual starter, at quarterback. The NFC South should be a cakewalk for the Buccaneers.
The NFL offseason really doesn’t stop. It seems like every year the mayhem gets more and more ludicrous, and now in 2022, it’s gotten to the point where the American consciousness is almost ignoring March Madness because of it. What a world. The most recent bombshell came courtesy of the Bucs’ division rival Atlanta Falcons, who will be shipping their long-time quarterback Matt Ryan to the Indianapolis Colts in exchange for a third-round pick.
So what does this mean for the Buccaneers? It’s quite simple really. As of this writing, they are the only team in the division, and one of the few in the conference for that matter, with a proven quarterback. Due to this, their demolition job heading into January could not be more clear.
The Falcons are now in limbo at the position, as are the Carolina Panthers while they try and figure out their own carousel. It looks like Jameis Winston may be headed back to New Orleans, which certainly makes spice things up a bit, but no matter the flavor, the Buccaneers will always have the edge when it comes to quarterback.
Why? Well, their quarterback isn’t just any “proven” starter, even if he is going to be 45 when the season eventually kicks off. This is Tom Brady we are talking about. As we’ve said after the Davante Adams trade, the NFC is essentially a two-team race with the Bucs and the defending Super Bowl champion Los Angeles Rams.
The Rams swept the Buccaneers in 2021 and given the current state of the NFC, and the division, in particular, all of their focus should be on beating the Rams. The Tampa Bay Buccaneers’ road to the Super Bowl somehow just got easier, and their battles with Matt Ryan appear to be nothing but memories. They are head and shoulders above the rest of the NFC South as if they weren’t already to begin with.